ZeroJudge 解題筆記：e969. 大吃大喝 (Big eater)

作者：王一哲
日期：2025年2月16日



ZeroJudge 題目連結：e969. 大吃大喝 (Big eater)

解題想法

這題要很注意輸出的內容，很容易弄錯一些細節。

Python 程式碼

使用時間約為 20 ms，記憶體約為 3.3 MB，通過測試。

n, m, k = map(int, input().split())
t = 0
food = ("eats an Apple pie", "drinks a Corn soup")
imin = (32, 55)

if n < imin[k]:
    print("Wayne can't eat and drink.")
else:
    while n >= imin[k]:
        n -= imin[k]
        print(f"{t:d}: Wayne {food[k]:s}, and now he ", end="")
        if n == 0: print(f"doesn't have money.")
        elif n == 1: print(f"has 1 dollar.")
        else: print(f"has {n:d} dollars.")
        k = (k+1)%2
        t += m

C++ 程式碼

使用時間約為 7 ms，記憶體約為 336 kB，通過測試。

#include <iostream>
#include <string>
using namespace std;

int main() {
    int n, m, k; cin >> n >> m >> k;
    int t = 0;
    string food[2] = {"eats an Apple pie", "drinks a Corn soup"};
    int imin[2] = {32, 55};

    if (n < imin[k]) {
        cout << "Wayne can't eat and drink.\n";
    } else {
        while(n >= imin[k]) {
            n -= imin[k];
            cout << t << ": Wayne " << food[k] << ", and now he ";
            if (n == 0) cout << "doesn't have money.\n";
            else if (n == 1) cout << "has 1 dollar.\n";
            else cout << "has " << n << " dollars.\n";
            k = (k+1)%2;
            t += m;
        }
    }
    return 0;
}